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Y' 2y x = y 2x, and (Equation 1) If the first derivative y'=0 , then (If , then A=0 ) y 2x = 0 , so that y = 2x Substituting this into the original equation x 2 xy y 2 = 3 leads to x 2 x (2x) (2x) 2 = 3 , x 2 2x 2 4x 2 = 3 , 3x 2 = 3 , x 2 = 1 , and Thus, the maximum value of y occurs when x=1 and y=2 , ie, at the 问号运算符是三目运算符,格式为表达式1? 表达式2:表达式3;如果表达式1成立,则执行表达式2,否则执行表达式3。 对于本题,是执行y>2?65的结果赋给变量x。 y>2?65,如果y>2,则表达式的值是6,并将值赋给变量x,x=6;否则表达式的值是5,并将值赋给变量xXy=2 xy=6 This question is from textbook Answer by lyra(94) (Show Source) You can put this solution on YOUR website!




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